Question

Three objects are positioned along the x axis as follows: 4.4 kg at x = + 1.1 m, 3.7 kg at x = +0.80 m, and 2.9 kg at x = +1.6 m. The acceleration due to gravity is the same everywhere. What is the location of the center of gravity for this system? Group of answer choices

Answer 1

Answer:

the distance from the location of the center of gravity to the location of the center o mass for this system is 1.13m

Explanation:

Given that

m₁=4.4kg

x₁=+1.1m

m₂=3.7kg

x₂=+0.80m

m₃=2.9kg

x₃=+1.6m

The position of the center of mass is

         Xcm = [m₁x₁ +m₂x₂ +m₃x₃]/(m₁+m₂+m₃)

                = [(4.40kg)(1.1 m)+(3.70 kg)(0.80 m)+(2.90 kg)(1.60 m)]/(4.4 kg + 3.70 kg+2.90 kg)

              = 1.13 m

The position of the center of gravity is 1.13m

Therefore, the distance from the location of the center of gravity to the location of the center o mass for this system is 1.13m

Answer 2

The distance from the location of the center of gravity should be to the location of the center of mass for this system is 1.13m

Calculation of the location of the center of gravity:

Since

m₁=4.4kg

x₁=+1.1m

m₂=3.7kg

x₂=+0.80m

m₃=2.9kg

x₃=+1.6m

Now

The position of the center of mass is

Xcm = [m₁x₁ +m₂x₂ +m₃x₃]/(m₁+m₂+m₃)

               = [(4.40kg)(1.1 m)+(3.70 kg)(0.80 m)+(2.90 kg)(1.60 m)]/(4.4 kg + 3.70 kg+2.90 kg)

= 1.13 m

The position of the center of gravity is 1.13m

Learn more about gravity here: https://brainly.com/question/24814067