Answer:
[tex]n_{NH_3}=0.18molNH_3[/tex]
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
[tex]H_3PO_4(aq)+3NH_3(l)\rightarrow (NH_4)_3PO_4[/tex]
In such a way, considering the 3 to 1 molar relationship between ammonia and ammonium phosphate, the moles of ammonia result:
[tex]n_{NH_3}=0.060mol(NH_4)_3PO_4*\frac{3molNH_3}{1mol(NH_4)_3PO_4}\\n_{NH_3}=0.18molNH_3[/tex]
Best regards.