Answer:
21.2 kJ/mol
Explanation:
Let's consider the following reaction for the synthesis of nitric acid.
NaNO₃(s) + H₂SO₄(l) → NaHSO₄(s) + HNO₃(g)
We can calculate the standard enthalpy of the reaction (ΔH°rxn) using the following expression.
ΔH°rxn = ∑ np × ΔH°f(p) - ∑ nr × ΔH°f(r)
where,
n: moles
ΔH°f: standard enthalpy of formation
p: products
r: reactants
ΔH°rxn = 1 mol × ΔH°f(NaHSO₄) + 1 mol × ΔH°f(HNO₃) - 1 mol × ΔH°f(NaNO₃) - 1 mol × ΔH°f(H₂SO₄)
ΔH°rxn = 1 mol × (-1125.5 kJ/mol) + 1 mol × (-135.1 kJ/mol) - 1 mol × (-467.8 kJ/mol) - 1 mol × (-814.0 kJ/mol)
ΔH°rxn = 21.2 kJ/mol