Respuesta :
Answer:
Answer for the question is given in the attachment.
Explanation:


The velocity of water and the force required to hold the nozzle is required.
The exit velocity is [tex]39.79\ \text{m/s}[/tex]
The force required is [tex]7958\ \text{N}[/tex]
[tex]\rho[/tex] = Density of water = [tex]1000\ \text{kg/m}^3[/tex]
d = Diameter = 8 cm
r = Radius = 4 cm
V = Volume flow rate = [tex]12\ \text{m}^3/\text{min}[/tex]
Velocity is given by
[tex]v=\dfrac{V}{A}\\\Rightarrow v=\dfrac{12}{\pi 0.04^2}\\\Rightarrow v=2387.32\ \text{m}^3/\text{min}\\\Rightarrow v=\dfrac{2387.32}{60}\\\Rightarrow v=39.79\ \text{m/s}[/tex]
Mass flow rate is
[tex]m=\rho V\\\Rightarrow m=1000\times \dfrac{12}{60}\\\Rightarrow m=200\ \text{kg/s}[/tex]
Force is given by
[tex]F=mv\\\Rightarrow F=200\times 39.79\\\Rightarrow F=7958\ \text{N}[/tex]
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