Answer:
The mean of this sampling distribution is 63.5 and the standard deviation of this sampling distribution is 0.5
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
[tex]\mu = 63.5, \sigma = 2.5, n = 25, s = \frac{2.5}{\sqrt{25}} = 0.5[/tex]
So the correct answer is:
The mean of this sampling distribution is 63.5 and the standard deviation of this sampling distribution is 0.5