Question

In a television picture tube the electrons are accelerated from rest through a potential difference V. Just before an electron strikes the screen, its de Broglie wavelength is 8.00 10-12 m. What is the potential difference

Answer 1

Answer:

V = 23515.53volt

Explanation:

wavelength λ= 1.1 x 10 -11 m

We know λ= h /√ [2mVq]

Where h = Plancks constant

            = 6.625 x 10 -34 J s

        m = mass of electron

           = 9.11 x 10 -31 kg

         q = charge of eectron

           =1.6 x 10 -19 C

From above potential difference V = ( 1/2mq) (h /λ)²

$V = (\frac{1}{2mq} )(\frac{h}{\lambda} )^2$

$V = (\frac{1}{2\times9.11\times10^{-31}\times1.6\times10^{-19}} )(\frac{6.625\times10^{-34}}{8\times10^{-12}} )^2$

$V = (\frac{1}{2.9152\times10^{-49}} )(8.28\times10^{-23} )^2\\\\V= (3.43\times10^{48})(6.85\times10^{-45})\\\\V = 23515.53volt$

V = 23515.53volt