Title:
Step-by-step explanation:
As all the questions of the exam carry 2 points, at least [tex]\frac{56}{2} = 28[/tex] questions need to be correct to get 56 marks.
In order to get a maximum of 56 marks, at most 28 answers needs to be correct.
Every question has two option. Hence, the probability of getting a particular question right is [tex]\frac{1}{2}[/tex].
The probability that exactly n questions will be right is [tex]^{50}C_n (\frac{1}{2} )^n (\frac{1}{2} )^{50 - n} = ^{50}C_n (\frac{1}{2} )^{50}[/tex].
The probability that at most 28 questions will be right is ∑[tex]^{50}C_n (\frac{1}{2} )^{50}[/tex], [tex]0\leq n\leq 28[/tex].
Similarly, the probability that at least 30 questions will be right is ∑[tex]^{50}C_n (\frac{1}{2} )^{50}[/tex], [tex]30\leq n \leq 50[/tex].