Answer:
0.48 V
Explanation:
Zn(s) ------------> Zn^2+(aq) + 2e. Oxidation half equation (-0.76V)
Co^2+(aq) + 2e-----------> Co(s). Reduction half equation (-0.28)
Zn(s) + Co^2+(aq) -------------> Zn^2+(aq) + Co(s) overall redox equation
Zinc is the anode while cobalt is the cathode.
E°cell= E°cathode - E°anode
E°cell= -0.28-(-0.76)= 0.48 V
Answer:
Explanation:
Half cell equations:
Oxidation
Zn(s) --> Zn2+(aq) + 2e-
E° = 0.7618 V
Reduction
Co2+(aq) + 2e- --> Co(s)
E° = -0.28 V
Balanced net ionic equation
Co2+(aq) + Zn(s) --> Zn2+(aq) + Co(s)
Standard electrode potential, E°cell = E°cathode - E°anode
For an electrochemical reaction,
Standard electrode potential, E°cell = E°reduction - E°oxidation
= -0.28 - (0.7618)
= -1.0418 V