Answer:
Recoil speed, [tex]1.17\times 10^{-5}\ m/s[/tex]
Explanation:
Given that,
Mass of the comet fragment, [tex]m_1=1.96\times 10^{13}\ kg[/tex]
Speed of the comet fragment, [tex]v_1=6.5\times 10^4\ m/s[/tex]
Mass of Callisto, [tex]m_2=1.08\times 10^{23}\ kg[/tex]
The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,
[tex]m_1v_1=(m_2+m_2)V[/tex]
V is recoil speed of Callisto immediately after the collision.
[tex]V=\dfrac{m_1v_1}{(m_2+m_2)}\\\\V=\dfrac{1.96\times 10^{13}\times 6.5\times 10^4}{(1.96\times 10^{13}+1.08\times 10^{23})}\\\\V=1.17\times 10^{-5}\ m/s[/tex]
So, the recoil speed of Callisto immediately after the collision is [tex]1.17\times 10^{-5}\ m/s[/tex]