Respuesta :
Answer:
Mean = 60
Median = 56
Mode = 53
70th percentile = 62
Explanation:
We have the following salaries in thousand of dollars:
A 53
B 44
C 68
D 47
E 62
F 59
G 53
H 94
The sample size is n=8.
a) The mean of this sample is:
[tex]\mu=\frac{1}{8} \sum_{i=1}^8x_i=\frac{1}{8} (53+44+68+47+62+59+53+94)\\\\ \mu=\frac{1}{8}*480=60[/tex]
b) The median, as its an even size sample, is the average between the middlemost salaries:
[tex]M=\frac{53+59}{2}=\frac{112}{2}=56[/tex]
c) The mode is the the value that appears the most in the sample.
In this case, the mode is 53, that appears twice.
d) The 70th percentile divides the sample with 70% of the values below and 30% above the percentile.
In this case, the 70th percentile lies in the 6th place of the sorted sample.
[tex]i=0.7*n=0.7*8=5.6\approx 6[/tex]
The sixth place for the sorted sample [44, 47, 53, 53, 59, 62, 68, 94] is 62.
