Given that JKV is a triangle.
We need to determine the translated image of the coordinate V using the rule [tex](x, y) \rightarrow(x-3, y+6)[/tex]
New point V:
The coordinate of the point V is (4,-1)
The new point V can be determined using the rule [tex](x, y) \rightarrow(x-3, y+6)[/tex]
Now, substituting the point (4,-1) in the rule, we get;
New point = [tex](4-3,-1+6)[/tex]
Simplifying the terms, we get;
New point = [tex](1,5)[/tex]
Thus, the coordinate of the new point V is (1,5)
