Answer:[tex]2.05 m/s^2[/tex]
Explanation:
Given
Mass of crate is [tex]m=25\ kg[/tex]
coefficient of kinetic friction [tex]\mu _k=0.25[/tex]
Larry Pushes with a force of [tex]F_L=400\ N[/tex] to the right
Moe pushes with a force of [tex]F_m=250\ N[/tex] to the left
Curly Pushes downward with a force of [tex]F_c=150\ N[/tex]
Net Normal reaction on the ground is
[tex]N=mg+F_c[/tex]
[tex]N=25\times 9.8+150=395\ N[/tex]
Friction force is given by [tex]f=\mu _k\cdot N[/tex]
[tex]f=0.25\times 395[/tex]
[tex]f=98.75\ N[/tex]
Friction Force always opposes the motion
Net Horizontal force on the box is
[tex]F_{net}=400-250-98.75[/tex]
[tex]F_{net}=51.25\ N[/tex]
acceleration is given by
[tex]a=\frac{F_{net}}{m}[/tex]
[tex]a=\frac{51.25}{25}[/tex]
[tex]a=2.05\ m/s^2[/tex]