An automobile tire having a temperature of −1.5 ◦C (a cold tire on a cold day) is filled to a gauge pressure of 26 lb/in2 . What would be the gauge pressure in the tire when its temperature rises to 40◦C? For simplicity, assume that the volume of the tire remains constant, that the air does not leak out and that the atmospheric pressure remains constant at 14.7 lb/in2 . Answer in units of lb/in2 .

Respuesta :

Answer:[tex]32.22\ lb/in^2[/tex]

Explanation:

Given

Temperature on the hot day [tex]T_i=-1.5^{\circ} C\approx 271.5\ K[/tex]

Gauge Pressure [tex]P_i=26\ lb/in^2[/tex]

When Temperature rises to [tex]T_f=40^{\circ}C\approx 313\ K[/tex] on a hot day then

absolute pressure  is let say [tex]P_f[/tex]

Using ideal gas equation we can write

[tex]\Rightarrow \frac{PV}{T}=constant [/tex]

as volume is constant therefore

[tex]\Rightarrow \frac{P}{T}=constant[/tex]

[tex]\Rightarrow \frac{26+14.7}{271.5}=\frac{P_f}{313}[/tex]

[tex]\Rightarrow P_f=46.92\ lb/in^2[/tex]

Gauge Pressure is given by

[tex]\Rightarrow 46.92-14.7=32.22\ lb/in^2[/tex]

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