Answer:[tex]32.22\ lb/in^2[/tex]
Explanation:
Given
Temperature on the hot day [tex]T_i=-1.5^{\circ} C\approx 271.5\ K[/tex]
Gauge Pressure [tex]P_i=26\ lb/in^2[/tex]
When Temperature rises to [tex]T_f=40^{\circ}C\approx 313\ K[/tex] on a hot day then
absolute pressure is let say [tex]P_f[/tex]
Using ideal gas equation we can write
[tex]\Rightarrow \frac{PV}{T}=constant [/tex]
as volume is constant therefore
[tex]\Rightarrow \frac{P}{T}=constant[/tex]
[tex]\Rightarrow \frac{26+14.7}{271.5}=\frac{P_f}{313}[/tex]
[tex]\Rightarrow P_f=46.92\ lb/in^2[/tex]
Gauge Pressure is given by
[tex]\Rightarrow 46.92-14.7=32.22\ lb/in^2[/tex]