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Given:-
perimeter of rectangle=26cm
Area of rectangle=>30cm²
{•°• perimeter of rectangle=2(l+b) }
{•°•. Area of rectangle=lxb}
So, 2(l+b)=26
=>(l+b)=26/2
=>l+b=13
=>l=(13-b) ----------(1)
Again,
=>lxb=30
=>(13-b)xb=30 {putting the value of l from equation 1}
=>13b-b²=30
=>b²-13b+30=0
=>b²-10b-3b +30=0
=>b(b-10)-3(b-10)=0
=>(b-10)(b-3)=0
or,
=>b=10 or b=3
putting the value of b in equation (1)
=>l=(13-b)
=>l=13-10=3 { taking b=10}
=>l=13-3=10 { taking b=3}
Hence, length=3 when breadth=10
length=10 when breadth=3
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