Respuesta :
Answer:
[tex]C.\ \ \ \\\\\x\geq 0\ \ \ ,y\geq 0\\\\0.5x+y\leq 500\\\\x+1.5y\leq 800[/tex]
Step-by-step explanation:
We first denote the inequalities of the number of shirts and skirts.
#Since you cannot make a negative number of shirts or skirts, the inequalities will be written as:
[tex]Shirts=> x\geq 0\\\\skirts=>y\geq 0[/tex]
#We then represent the inequality of material.
-The material size is a production constraint as only 500 yards of material is available for use.
-The inequality is therefore written as:
[tex]x \ takes \ 0.5\ yards\\y\ takes \ 1 \ yard\\\\\therefore 0.5x+y\leq 500[/tex]
#We then represent the inequality of time.
-The material size is a production constraint as only 800 hours available for use.
-The inequality is therefore written as:
[tex]x \ takes\ 1 \ hr\\y \ takes\ 1.5 \ hr\\\\\therefore x+1.5y\leq 800[/tex]
We combine the three inequalities to represent the constraints
[tex]x\geq 0\ \ \ ,y\geq 0\\\\0.5x+y\leq 500\\\\x+1.5y\leq 800[/tex]
Answer:
x ≥ 0 and y ≥ 0
0.5x + y ≤ 500
x + 1.5y ≤ 800
When graphed the system shows that the manufacturer should make 200 shirts and 400 skirts for a maximum profit.
so the answer is C
Step-by-step explanation: