Question

In ΔDEF, the measure of ∠F=90°, the measure of ∠E=32°, and FD = 9.6 feet. Find the length of EF to the nearest tenth of a foot.

Answer 1

Answer:

$EF=15.4\ ft$

Step-by-step explanation:

we know that

In the right triangle DEF

$tan(E)=\frac{FD}{EF}$ ----> by TOA (opposite side divided by adjacent side)

substitute the given values

$tan(32^o)=\frac{9.6}{EF}$

solve for EF

$EF=\frac{9.6}{tan(32^o)}=15.4\ ft$

Answer 2

Answer:

EF=15.4 ft

Step-by-step explanation:

I got it right on delta math so ig its right