The constant of the equation so that it has solutions of -5 and 7 is -35
Quadratic equation
The solutions of a quadratic equation area known as the zeros of the equation
Given the zeros
x = -5 and 7
Find the factors
(x + 5)(x -7)
Expand the factors
f(x) = x^2 - 7x + 5x - 35
f(x) = x^ - 2x - 35
Hence the constant of the equation so that it has solutions of -5 and 7 is -35
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