Question

A restaurant serves custom-made omelets, where guests select meat, cheese, and vegetables to be added to their omelet. There are 6 vegetables available, and guests may select any 2 vegetables for their omelet. How many different combinations of 2 vegetables are possible?

Answer 1

Answer: The number of different combinations of 2 vegetables are possible = 15 .

Step-by-step explanation:

In Mathematics , the number of combinations of selecting r values out of n values = $^nC_r=\dfrac{n!}{r!(n-r)!}$

Given : Number of available vegetables = 6

Then, the number of different combinations of 2 vegetables are possible will be :

$^6C_2=\dfrac{6!}{2!(6-2)!}=\dfrac{6\times5\times4!}{2\times4!}=15$

Hence , the number of different combinations of 2 vegetables are possible = 15 .

Answer 2

Using the combination formula, it is found that 15 different combinations of 2 vegetables are possible.

The order in which the vegetables are chosen is not important, hence, the combination formula is used to solve this question.

Combination formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this problem, 2 vegetables are chosen from a set of 6, hence:

$C_{6,2} = \frac{6!}{2!4!} = 15$

15 different combinations of 2 vegetables are possible.

To learn more about the combination formula, you can check https://brainly.com/question/25990169