Answer:
The answer to your question is Momentum = [tex]\frac{(x + 2)^{2}}{x - 3}[/tex]
Step-by-step explanation:
Data
mass = [tex]\frac{x^{2}+ 4x + 4 }{x^{2}- 9}[/tex]
velocity = [tex]\frac{x^{2}+ 5x + 6}{x + 2}[/tex]
Formula
Momentum = mass x velocity
Substitution
Momentum = [tex]\frac{x^{2}+ 4x + 4}{x^{2}- 9} \frac{x^{2} + 5x + 6}{x + 2}[/tex]
Factor The first numerator is a perfect square trinomial and the second one is a trinomial of the form x² + bx + c.
Momentum = [tex]\frac{(x + 2)^{2}}{(x - 3)(x + 3)} \frac{(x + 2)(x + 3)}{x + 2}[/tex]
Simplify and result
Momentum = [tex]\frac{(x + 2)^{2}}{x - 3}[/tex] or [tex]\frac{x^{2} + 4x + 4}{x - 3}[/tex]
