A pack of four Arctic wolves are exerting four different forces upon the carcass of a 500 kg dead polar bear. Wolf one is pulling on the bear with a force of 20 Newtons (N) due north. Wolf two is pulling on the bear with a force of 30 N, 30 degrees north of west. Wolf three is pulling on the bear with a force of 25 N due west, and wolf four is pulling on the bear with a force of 35 N, 10 degrees west of south. Determine the net force acting upon the polar bear and the direction of that force measured north of west.

Respuesta :

Answer:

F = 58.1N

θ = 10.4° South of East.

Explanation:

Let the situation be as represented in the diagram attached. To determine the net force acting on the bear, we need to resolve the forces into component forms.

Taking west-east as the +x axis and south-north as +y axis.

F1x = 0N (force is directed due north and so has not x component)

F2x = – F2cos30° = –30cos30° = –26N

F3x = – 25N (force is directed due west and so has only x component)

F4x = –F4sin10° = -35sin10° = –6.08N

Fx = F1x + F2x + F3x + F4x =0 – 26 –25 – 6.08 = –57.08N

F1y = 20N (force is directed due north and so has not x component)

F2y = F2sin30° = 30sin30° = 15N

F3y = 0N (force is directed due west and so has only x component)

Fy = –F4cos10° = -35cos10° = –34.5N

Fy = F1y + F2y + F3y + F4y = 20 + 15 + 0 –34.5 = –10.5N

F = √(Fx² + Fy²)

F = √((-57.1² + (-10.5)²) = 58.1N

θ = tan-¹(Fy/Fx) = tan-¹(-10.5/-57.1) = 10.4° South of East.

F = 58.1N

θ = 10.4° South of East.

Ver imagen akande212

The net force acting upon the polar bear is : 58.1 N

The direction of the net force measured is  : 10.4° South of East.

Calculate the net force and direction of force

F₁y = 20N      no x component

F₂y = F₂* sin 30° = 30 * sin 30° = 15N

F₃y = 0 N       only x component)

while :

Fy = –F₄Cos10°

    = -35 * cos10°

    = –34.5 N.

Summation of forces in along th y component

Fy = F₁ y +  F₂y + F₃y + F₄y

    = 20 + 15 + 0 – 34.5

    = – 10.5N

Therefore  F = √(Fx² + Fy²)

                    = √((-57.1² + (-10.5)²)

                    = 58.1N

Next step : Determine the direction of the force

θ = tan-¹( Fy / Fx )

  = tan-¹( -10.5 / -57.1 )

   = 10.4° South of East.

Hence we can conclude that the net force (  F ) = 58.1 N and the direction of the net force is  10.4° South of East.

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