Answer:
20.18 J
Explanation:
We are given that
Mass of bx=m=1.1 kg
Height=h=1.75 m
Initial speed of box=u=2.99 m/s
Final speed,v=2.56 m/s
We have to find the mechanical energy lost due to friction.
Energy at top=[tex]K.E+P.E=\frac{1}{2}mu^2+mgh=\frac{1}{2}(1.1)(2.99)^2+1.1\times 9.8\times 1.75=23.78[/tex] J
Where [tex]g=9.8 m/s^2[/tex]
At bottom,h'=0
Energy at bottom=[tex]\frac{1}{2}mv^2+mgh'=\frac{1}{2}(1.1)(2.56)^2+0=3.6 J[/tex]
Energy lost=Energy(Top)-Energy(bottom)=23.78-3.6=20.18 J
