Question

can someone help me please ​

Answer 1

Given:

Base of the triangle = 4

Height of the triangle = x

Hypotenuse of the triangle = x

To find:

The value of x.

Solution:

The given triangle is a right triangle.

Using Pythagoras theorem:

$\text{Base}^2+\text{Height}^2=\text{Hypotenuse}^2$

${4}^2+{x}^2={5}^2$

$16+{x}^2=25$

Subtract 16 from both sides.

$16+{x}^2-16=25-16$

${x}^2=9$

Taking square root on both sides.

$\sqrt{{x}^2}=\sqrt{9}$

$x=3$

The value of x is 3.