Respuesta :
Answer:
a. 121 Btu/lb
b. 211.8lb
c. 2.69/pc
Explanation:
See the attachments please




Answer:
a) The unit energy for melting and pouring is 121 Btu/lb
b) The total cost per hour is 368.31/h
c) The cost per part is 2.7/pc
Explanation:
a) The unit energy for melting and pouring is:
[tex]U=C_{p} (T_{m,Zn} -T_{0} )+deltaH_{fus}+C_{p} (T_{p}- T_{0})[/tex]
If we assume that the surrounding temperature is 70°F
[tex]U=0.091(787-70)+49+0.091(860-787)=121Btu/lb[/tex]
b) The hourly production is:
[tex]R=(\frac{number-of-castings}{t_{cycle} } )*(1-scrap-rate)\\R=(\frac{2}{0.85min} *\frac{60min}{1h} )*(1-0.03)=136.9good-parts/h[/tex]
The total weight of zinc is:
[tex]W_{total} =(\frac{number-of-castings}{t_{cycle} } )*(2*weight-of-casting)\\R=(\frac{2}{0.85min} *\frac{60min}{1h} )*(2*0.75)=211.8lb[/tex]
The total cost of zinc is:
[tex]C=W_{total} *cost-of-zinc=211.8*1.05=222.3[/tex] $
The total heat transfer is:
[tex]Q=(\frac{number-of-castings}{t_{cycle} } )*((2*weight-of-casting)+gating-system-weight)*U\\Q=(\frac{2}{0.85min} *\frac{60min}{1h} )*((2*0.75)+0.4))*121=32462Btu/h=541Btu/min[/tex]
541 Btu/min = 9.51 kW
The power is:
[tex]Power=\frac{Q}{1-Q_{loss} } =\frac{9.51}{1-0.35} =14.6kW[/tex]
The hourly cost is:
[tex]C_{H} =P*cost-of-power-for-heating=14.6*0.15=2.2/h[/tex]
The cost for die casting is:
[tex]C_{d} =cost-rate-of-die-casting+(2*cost-of-each-robot)=57+(2*18)=93/h[/tex]
The die cost per casting is:
[tex]C_{die,casting} =\frac{45000}{200000} =0.225/pc[/tex]
The hourly rate is:
[tex]Hourly-rate=R*C_{d,casting} =136.9*0.225=30.81/h[/tex]
The total cost per hour is:
[tex]C_{total} =C+C_{H} +C_{d} +C_{1} +Hourly-time=222.35+2.2+93+20+30.81=368.31/h[/tex]
c) The cost per part is:
[tex]C_{per part} =\frac{C_{total} }{R} =\frac{368.36}{136.9} =2.7/pc[/tex]