Answer:
The answer to your question is (x + 3)
Step-by-step explanation:
[tex]\frac{5x + 5}{x} \frac{x^{3}+ 3x^{2}}{x^{2} - 1} \frac{x - 1}{5x}[/tex]
Factor the expression
[tex]\frac{5(x + 1)}{x} \frac{x^{2}(x + 3)}{(x - 1)(x + 1)} \frac{x - 1}{5x}[/tex]
Simplify
Cancel 5 because is in both numerator and denominator
Cancel (x + 1) because is in both numerator and denominator
Cancel (x - 1) because is in both numerator and denominator
Cancel x² because is in both numerator and denominator
After simplifying, the result is (x + 3)
