Question

What is the volume of 2.4 mol of an ideal gas at a pressure of 3 atm and a temperature of 0◦ C?1liter=0.001m3 and1atm=101300 Pascals. Answer in units of L.

Answer 1

Answer:

volume of the gas is 17.9 Ltr

Explanation:

As we know by ideal gas equation

PV = nRT

here we know that

n = 2.4 mol

T = 0 degree C

P = 3 atm

now from above equation we have

$(3 \times 101300) V = 2.4 (8.31)(273)$

so we have

$V = 17.9 \times 10^{-3} m^3$

so volume of the gas is 17.9 Ltr

Answer 2

The volume of the gas will be "17.9 ltr". To understand the calculation, check below.

Ideal Gas Equation

According to the question,

Number of moles, n = 2.4 mol

Temperature, T = 0°C

Pressure, P = 3 atm

By using the Ideal gas equation,

→ PV = nRT

or,

The Volume be:

→ V = $\frac{nRT}{P}$

By substituting the values, we get

      = $\frac{2.4\times 8.31\times 273}{3\times 101300}$

      = 17.9 × 10⁻³ m³ or,

      = 17.9 Ltr

Thus the response above is correct.

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