To solve this problem we will apply the concepts related to Ohm's law and Electric Power. By Ohm's law we know that resistance is equivalent to,
[tex]R_{eq}= \frac{V}{I}[/tex]
Here,
V = Voltage
I = Current
While the power is equivalent to the product between the current and the voltage, thus solving for the current we have,
[tex]P=VI \rightarrow I = \frac{P}{V}[/tex]
[tex]I =0.608 A[/tex]
Applying Ohm's law
[tex]R_{eq} = \frac{120V}{0.608A}[/tex]
[tex]R_{eq} = 197.4\Omega[/tex]
Therefore the equivalent resistance of the light string is [tex]197.4\Omega[/tex]