Given:
ABC is a right triangle.
Opposite of C = AB = 6
Adjacent of C = BC = 8
Hypotenuse = AC = 10
To find:
The value of sin C.
Solution:
Using basic trigonometric ratio formula:
[tex]$\sin \theta = \frac{\text{Opposite of }\theta}{\text{Hypotenuse}}[/tex]
[tex]$\sin C = \frac{\text{Opposite of C}}{\text{Hypotenuse}}[/tex]
[tex]$\sin C = \frac{AB}{AC}[/tex]
[tex]$\sin C = \frac{6}{10}[/tex]
Cancel the common factors.
[tex]$\sin C = \frac{3}{5}[/tex]
The value of sin C is [tex]\frac{3}{5}[/tex].
