Respuesta :
Answer:
The constant angular acceleration of the centrifuge = -252.84 rad/s²
Explanation:
We will be using the equations of motion for this calculation.
Although, the parameters of this equation of motion will be composed of the angular form of the normal parameters.
First of, we write the given parameters.
w₀ = initial angular velocity = 2πf₀
f₀ = 3650 rev/min = (3650/60) rev/s = 60.83 rev/s
w₀ = 2πf₀ = 2π × 60.83 = 382.38 rad/s
θ = 46 revs = 46 × 2π = 289.14 rad
w = final angular velocity = 0 rad/s (since the centrifuge come rest at the end)
α = ?
Just like v² = u² + 2ay
w² = w₀² + 2αθ
0 = 382.38² + [2α × (289.14)]
578.29α = -146,214.4644
α = (-146,214.4644/578.29)
α = - 252.84 rad/s²
Hope this Helps!!!
Answer:
Explanation:
Given:
Initial angular velocity, wi = 3650 rev/min
Converting from rev/min to rad/sec,
3650 rev/min × 2pi rad/1 rev × 1 min/60 secs
= 382.23 rad/s
Final angular velocity, wf = 0 rad/s (comes to rest)
Angular displacement, Ѳ = 46 times
= 46 revs
= 46 rev × 2pi rad/1 rev
= 289.03 rad
Using equation of angular motion,
wf^2 = wi^2 + 2 × ao × Ѳ
Where,
ao = angular acceleration
0 = 382.23^2 + 2 × 289.03 × ao
Solving for ao,
ao = -252.75 rad/s^2
