Given:
Triangle DEF
To find:
The perimeter of triangle DEF.
Solution:
Coordinate of D = (-1, 1)
Coordinate of E = (2, 1)
Coordinate of F = (-1, 4)
Distance formula:
[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
Distance of DE:
Here, [tex]x_1=-1, y_1=1, x_2=2, y_2=1[/tex]
[tex]d=\sqrt{(1-1)^2+(2-(-1))^2}[/tex]
[tex]d=\sqrt{0+9}[/tex]
d = 3 units
Distance of EF:
Here, [tex]x_1=2, y_1=1, x_2=-1, y_2=4[/tex]
[tex]d=\sqrt{(4-1)^2+(-1-2)^2}[/tex]
[tex]d=\sqrt{9+9}[/tex]
[tex]d=\sqrt{18}[/tex]
d = 4.2 units
Distance of FD:
Here, [tex]x_1=-1, y_1=4, x_2=-1, y_2=1[/tex]
[tex]d=\sqrt{(1-4)^2+(-1-(-1))^2}[/tex]
[tex]d=\sqrt{9+0}[/tex]
d = 3 units
Perimeter of ΔDEF = DE + FE + FD
= 3 + 4.2 + 3
= 10.2 units
The perimeter of triangle DEF is 10.2 units.