Answer:
The value of variable capacitor is [tex]1.89 \times 10^{-13}[/tex] F
Explanation:
Given :
Inductance [tex]L = 250 \times 10^{-3}[/tex] H
Frequency [tex]f = 731 \times 10^{3}[/tex] Hz
According to the cutoff frequency,
[tex]f = \frac{1}{2\pi \sqrt{LC} }[/tex]
Now we find the value of capacitance,
[tex]C = \frac{1}{4\pi ^{2} f^{2} L }[/tex]
[tex]C = \frac{1}{4\times 9.85 \times (731 \times 10^{3} )^{2} \times 250 \times 10^{-3} }[/tex]
[tex]C = 1.89 \times 10^{-13}[/tex] F
Therefore, the value of variable capacitor is [tex]1.89 \times 10^{-13}[/tex] F