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  • 30-03-2020
  • Mathematics
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In the function f(x) = (x - 2)^2 + 4, the minimum occurs at

Respuesta :

jimrgrant1 jimrgrant1
  • 30-03-2020

Answer:

4

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

The max/ min of the function is the value of k

f(x) = (x - 2)² + 4 ← is in vertex form

with (h, k) = (2, 4 ) → k = 4

Thus minimum occurs at 4

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