Respuesta :
Answer:
Explanation:
Given that,
Height = 46m
Then, final height is y=-46m
Initial height yo=0m
Time to reach height is 5sec
a. Initial speed
Using equation of motion
y-yo = vot - ½gt²
-46-0 = vo• 5- ½×9.8×5²
-46 =5vo -122.5
5vo = -46+122.5
5vo =76.5
vo = 76.5/5
vo= 15.3m/s upward.
vo = 15.3m/s
b. How high does it rise
Using equation of free fall
At maximum height, the final velocity is 0m/s
v² = u² - 2gH
0² = 15.3² -2•9.8H
-15.3² = -19.6H
H=15.3²÷19.6
H=11.943m
Maximum height 11.943m
c. At maximum height the velocity is zero this is due to gravity provides the same acceleration to the ball on the way up (slowing it down) as on the way down (speeding it up), the time to reach maximum altitude is the same as the time to return to its launch position.
d. The magnitude of acceleration at the highest point is the same as the acceleration due to gravity(g=9.8m/s²).
e. The direction of the acceleration is downward, it is directed toward the negative y axis( -j)
a = -9.81m/s².
Answer:
A) 15.3 m/s
B) 11.94m
C) 0 m/s
D) 9.8 m/s²
E) Direction is downwards
Explanation:
A) If we take the origin at the cornice of the building and the positive y direction to be upward, we will arrive at the equation;
y - y_o = ut - (1/2)gt²
From the question, y_o = 0 m, y = 46 m and t = 5 s
Thus, we have;
-46 = 5u - (1/2)(9.8)(5²)
-46 = 5u - 122.5
5u = 122.5 - 46
u = 76.5/5 = 15.3 m/s
B) when the egg is at a maximum height, its final velocity there is zero. Thus using the equation ;
v² = u² - 2gy
So, 0² = 15.3² - 2(9.8y)
0 = 234.09 - 19.6y
So, 19.6y = 234.09
y = 234.09/19.6 = 11.94m
C) Magnitude of velocity at highest point is zero
D) At the highest point, the egg falls under the effect of gravity. Thus the acceleration due to gravity is constant and the value remains 9.8 m/s²
E) At the highest point, the egg falls under the effect of gravity. Thus the direction of acceleration due to gravity is constant throughout and the direction from this point is downwards.
