Answer:
69.66 Joule
Explanation:
mass of bicycle frame, mf = 8.29 kg
mass of wheel, mw = 0.820 kg
radius, r = 0.343 m
velocity, v = 3.6 m/s
There are two wheels in the bicycle.
There are two types of kinetic energy of the system one is kinetic energy of rotation and another is rotational kinetic energy.
[tex]K = \frac{1}{2}m_{f}v^{2}+ 2\times \frac{1}{2}m_{w}v^{2}+ 2\times \frac{1}{2}I_{w}\omega^{2}[/tex]
[tex]K = \frac{1}{2}m_{f}v^{2}+m_{w}v^{2}+ \frac{1}{2}\times m_{w}v^{2}[/tex]
[tex]K = \frac{1}{2}m_{f}v^{2}+ \frac{3}{2}\times m_{w}v^{2}[/tex]
[tex]K = \frac{1}{2}\times 8.29\times 3.6^{2}+ \frac{3}{2}\times 0.820\times 3.6^{2}[/tex]
K = 69.66 J