Answer:
Calculated molarity of acid is higher than the actual concentration.
Explanation:
For an acid-base titration, the following equation is obeyed for calculation-
[tex]C_{acid}.V_{acid}=C_{base}.V_{base}[/tex]
where, C represents concentration and V represents volume.
So, [tex]C_{acid}=\frac{C_{base}.V_{base}}{V_{acid}}[/tex]
Here, [tex]C_{base}[/tex] and [tex]V_{acid}[/tex] are constants.
Actual volume of base added from burette is lesser than the volume used (based on assumption) for calculation of concentration of acid.
So, actual value of [tex]V_{base}[/tex] is lesser. Hence calculated concentration or molarity of acid is higher than the actual concentration.