Respuesta :
Answer:
The voltage across the inductor I'm terms of I0, ω and L is expressed as V(t) = I0ωLsinωt
Explanation:
In an R-L AC circuit, the voltage across the inductor leads the current by 90°.
Voltage V(t) across the inductor can be expressed as
V(t) = V0sinωt ... (1) where;
ω is the angular velocity which is a function of its frequency.
Since the inductive reactance
XL = V0/I0
V0 = I0XL
also if XL = ωL
V0 = I0(ωL)...(2)
Substituting equation 2 into 1 to get V(t),
V(t) = I0ωLsin(ωt)
V(t) = I0ωLsinωt
The voltage across the inductor in terms of I0, ω and L is expressed as V(t) = I0ωLsinωt
The voltage V(t) across the inductor : V(t) = I₀ ωLsinωt
Given that :
Voltage across inductor leads current by 90° in an R-L-C circuit ( AC )
v(t) = v₀sinωt ------ ( 1 )
where : ω = angular velocity
Note: XL ( inductive reactance ) = v₀ / I₀
∴ v₀ = XL * I₀ ----- ( 2 )
where; XL = ωL
Back to equation ( 1 )
V(t) = I₀ ωLsinωt
Hence we can conclude that the voltage V(t) across the inductor : V(t) = I₀ ωLsinωt
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