Answer:
The takeoff speed of the flea is 1.98 m/s.
Explanation:
Consider upward direction as positive and downward direction as negative.
Given:
Length of the flea (L) = 2.0 mm
Mass of the flea (m) = 0.50 mg
Maximum height reached by the flea (h) = 20 cm = 0.20 m [1 cm =0.10 m]
At maximum height, velocity is 0. So, final velocity (v) = 0 m/s
Acceleration of the flea is only due to gravity (g) = -9.8 m/s² (Down)
Let the initial takeoff velocity be 'u' m/s.
We know that, from kinetic equation of motion, the final velocity is related to initial velocity, acceleration and displacement as:
[tex]v^2=u^2+2aS[/tex]
Where, 'a' and 'S' are the acceleration and displacement of the body respectively.
As per question,
[tex]a = g = -9.8[/tex] m/s²
[tex]S = h = 0.20\ m[/tex]
Plug in the given values and solve for 'u'. This gives,
[tex]0=u^2-2\times 9.8\times 0.20\\\\u^2=3.92\\\\\sqrt{u^2}=\sqrt{3.92}\\\\u=1.98\ m/s[/tex]
Therefore, the takeoff speed of the flea is 1.98 m/s.