Answer:
see explanation
Step-by-step explanation:
sin M = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{KL}{ML}[/tex] = [tex]\frac{2\sqrt{11} }{12}[/tex] = [tex]\frac{\sqrt{11} }{6}[/tex]
tan M = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{KL}{KM}[/tex] = [tex]\frac{2\sqrt{11} }{10}[/tex] = [tex]\frac{\sqrt{11} }{5}[/tex]
