Respuesta :

factors of  [tex]f(x) = 18x^2-9x-5[/tex]  are [tex]3x+1[/tex] and [tex]6x-5[/tex] .

Step-by-step explanation:

Here we have , to identify all factors of this expression . let's find out :

Expression : [tex]f(x) = 18x^2-9x-5[/tex]

⇒ [tex]f(x) = 18x^2-9x-5[/tex]

Now , -9x can be written as :

[tex]-9x=-15x+6x[/tex]

Putting this value

[tex]f(x) = 18x^2-15x+6x-5[/tex]

Taking out common terms we get

[tex]f(x) = 3x(6x-5)+6x-5[/tex]

[tex]f(x) = 3x(6x-5)+1(6x-5)[/tex]

[tex]f(x) = (3x+1)(6x-5)[/tex]

Therefore , factors of  [tex]f(x) = 18x^2-9x-5[/tex]  are [tex]3x+1[/tex] and [tex]6x-5[/tex] .

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