find the length of AB. round to the nearest tenth.

Answer: AB = 47 yds
Step-by-step explanation:
we would apply the law of Cosines which is expressed as
a² = b² + c² - 2abCosA
Where a,b and c are the length of each side of the triangle and A is the angle corresponding to a. Likening the expression to the given triangle, it becomes
AB² = 75² + 68² - 2(75 × 68)Cos38
AB² = 5625 + 4624 - 2(5100)Cos38
AB² = 10249 - 10200 × 0.788
AB² = 10249 - 8037.6
AB² = 2211.4
AB² = √2211.4
AB = 47 yds