Question

At 25°C, a saturated solution of cerium(III)
hydroxide (Ce(OH)3) contains 5.1 x 10-6 moles of
the compound in one liter of solution.
What is the reaction equation?
O Ce(OH)3(s) + Ce3+ (aq) + 3OH-(aq)
O Ce(OH)3(s) + Ce3+ (aq) + OH:(aq)
O 3Ce 3+ (aq) + OH (aq) +- Ce(OH)3(s)
O Ce(OH)3(s) + Ce 3+ (aq) + (OH-)3(aq)
DONE

Answer 1

Answer:

Ce(OH)3(s) —> Ce3+ (aq) + 3OH-(aq)

Explanation:

In solution, Ce(OH)3 will dissociate as follow:

Ce(OH)3(s) —> Ce3+(aq) + OH-(aq)

Now, we need to balance the charge on both side to obtain the balance equation. This is illustrated below:

There is 0 charge on the left and +2 charge on the right. It can be balance by putting 3 in front of OH- as shown below:

Ce(OH)3(s) —> Ce3+(aq) + 3OH-(aq)

Now we have 0 charge on both the left and right side of the equation. Therefore, the equation is balanced.

Answer 2

Question:

Fill in the blanks with the correct numbers to show the molar ration in the reaction equation. A:B:C

Answer:

1:1:3

Question:

What is the Ksp expression?

Answer:

A= 1

B= 3

Question:

What is the set-up for determining Ksp?

Answer:

Ksp = [X] ×[3X]^3

Question:

Calculate the value of Ksp.

Answer:

1.8 x 10^–20

Question:

What is the expression for the Ksp?

Answer:

Ksp = (Ca2+)(F-)^2

Question:

How does (Ca2+) compare to (F-)?

Answer:

1:2