Answer:
Speed of two cars is 20.6 m/s
Explanation:
As we know that there is no external force on the system of two cars
So momentum of the system will remain conserved before and after collision
So we will have
[tex]P_i = m_1v_1 \hat i + m_2 v_2 \hat j[/tex]
here we know
[tex]m_1 = 1800 kg[/tex]
[tex]v_1 = 30 m/s[/tex] towards west
[tex]m_2 = 1200 kg[/tex]
[tex]v_2 = 25 m/s[/tex]
so we have
[tex]P_i = (1800)(30)\hat i + (1200)(25)\hat j[/tex]
[tex]P_i = 54000\hat i + 30000\hat j[/tex]
now if finally two cars locked and moved together
[tex]P_f = (m_1 + m_2) v_f[/tex]
[tex]54000\hat i + 30000\hat j = (1200 + 1800) \vec v[/tex]
[tex]\vec v = 18\hat i + 10 \hat j[/tex]
so speed of two cars is given as
[tex]v = \sqrt{18^2 + 10^2}[/tex]
[tex]v = 20.6 m/s[/tex]