Question

#9 please help me solve this

Answer 1

Given:

Point (-6, -9)

Slope = $\frac{5}{2}$

To find:

Equation of a line in slope-intercept form

Solution:

Here $x_1=-6, y_1=-9$

$m=\frac{5}{2}$

Using point-slope formula:

$y-y_1=m(x-x_1)$

Substitute the values in the formula.

$y-(-9)=\frac{5}{2} (x-(-6))$

$y+9=\frac{5}{2} (x+6)$

$y+9=\frac{5}{2} x+\frac{5}{2}(6)$

Cancel common factor in 2 and 6, we get

$y+9=\frac{5}{2} x+5(3)$

$y+9=\frac{5}{2} x+15$

Subtract 9 from both sides.

$y+9-9=\frac{5}{2} x+15-9$

$y=\frac{5}{2} x+6$

The equation of a line in slope-intercept form is $y=\frac{5}{2} x+6$.

Answer 2

Answer:

y = (5/2)x + 6

Step-by-step explanation:

y = (5/2)x + c

-9 = (5/2)(-6) + c

-9 = -15 + c

c = 6

y = (5/2)x + 6