Question

What is the equation process to this question?

Evaluate the function to answer the question.

The height h, in feet, of a ball that is released 4 ft above the ground with an initial upward velocity of 80 ft/s is a function of the time t, in seconds, the ball is in the air and is given by the following.

h(t) = −16t^2 + 80t + 4, 0 ≤ t ≤ 5.04

(a) Find the height of the ball (in feet) above the ground 2 s after its released.

(b) Find the height of the ball (in feet) above the ground 4 s after its released.

Answer 1

$h(t) =-16t^2 + 80t + 4,\quad 0 \le t \le 5.04$

(a) Find the height of the ball (in feet) above the ground 2 s after its released.

That's just h(2)

h(2) = -16(2²) + 80(2) + 4 = -64 + 160 + 4 = 100

Answer: 100 feet

(b) Find the height of the ball (in feet) above the ground 4 s after its released.

That's just h(4)

h(4) = -16(4²) + 80(4) + 4 = -256 + 320 + 4 = 68

Answer: 68 feet