Answer:
Explanation:
You must assume that the ratio of the number of tickets in row 7 is a constant.
That permits you to set a proportion with the ratio of the number of tickets in row 7 for the first batch of tickets and the ratio of the number of tickets in row 7 for the next 33 tickets sent out:
1. Ratio of number of tickets in row 7 for the first batch.
- Number of tickets in row 7: 20
- Total number of tickets: 20 + 19 + 16 = 55
- Ratio: 20/55
2. Ratio of number of tickets in row 7 in the next 33 tickets sent out:
- Number of tickets in row 7: x
- Total number of tickets sent out: 33
- Ratio: x/33
3. Proportion
Set the proportion and solve for x:
[tex]\dfrac{20}{55}=\dfrac{x}{33}\\\\\\20\times 33=55x\\\\\\ x=\dfrac{20\times 33}{55}\\ \\ \\ x=\dfrac{20\times 3}{5}\\ \\ \\ x=4\times 3\\ \\ \\ x=12[/tex]
Answer: 12 tickets
