Question

which sum or difference identity could be used to prove that sin(pie + q) = -sin q

Answer 1

Answer:

see below

Step-by-step explanation:

sin(a+b) = sin(a)cos(b) + cos(a)sin(b)

sin(π+q) = sin(π)cos(q) + cos(π)sin(q)

sin(π) = 0

cos(π) = -1

therefore

sin(π+q) = 0*cos(q) -sin(q) = -sin(q)