Question

A pizza shop has available toppings of bacon, sausage, pepperoni, onions, anchovies, mushrooms, peppers and olives. How many different ways can a pizza be made with 3 toppings?

Answer 1

Answer: You have 336 possible combinations.

Step-by-step explanation:

The possible toppings are:

bacon, sausage, pepperoni, onions, anchovies, mushrooms, peppers, and olives.

so we have 8 possible toppings.

If we need to choose 3 different ones, we have that:

For the first one, we have 8 options.

For the second one, we have 7 options (because we already selected one)

For the third one, we have 6 options (because we already selected two)

So the total number of possible combinations is:

c = 8*7*6 = 336

Answer 2

There are 56 different ways of making pizza with 3 toppings

The number of available topping is given as

$n = 8$

The number of topping to select is given as:

$r = 3$

For different selections, we make use of the following combination formula

$^nC_r = \frac{n!}{(n-r)!r!}$

So, we have:

$^8C_3 = \frac{8!}{(8-3)!3!}$

Subtract 3 from 8

$^8C_3 = \frac{8!}{5!3!}$

Simplify the expression

$^8C_3 = \frac{8 \times 7 \times 6}{3 \times 2 \times 1}$

$^8C_3 = 8 \times 7$

$^8C_3 = 56$

Hence, there are 56 different ways of making pizza with 3 toppings

Read more about combination at:

https://brainly.com/question/11732255