Please help. Trig: Laws of Cosines
If a rhombus whose side measures 4 and the smaller angle is 64*, find the length of the larger diagonal, to the nearest tenth.

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Answer:

Correct answer:  d₁ = 6.8

Step-by-step explanation:

where is:

larger diagonal d₁ = ?

rhombus side a = 4

smaller (acute) angle α = 64°

The adjacent angles in the rhombus are complementary, meaning that their sum is 180 degrees.

We calculate the greater obtuse angle:

β = 180° - 64° = 116°  ⇒  β = 116°  

The larger diagonal and the two sides of the rhombus form a obtuse triangle

We obtain the required  larger diagonal using the cosine theorem:

d₁² = a² + a² - 2 · a² · cos β = 2 · a² - 2 · a² · cos β = 2 · a² ( 1 - cos β)

d₁² = 2 · a² ( 1 - cos β) = 2 · 4² ( 1 - cos 116°) = 32 ( 1 - (- 0.438))

d₁² = 32 · ( 1 + 0.438) = 46, 016  ⇒

d₁ = √46, 016 = 6.78 ≈ 6.8

d₁ = 6.8

God is with you!!!

Answer:

6.8

Step-by-step explanation:

Greater angle: 180 - 64 = 116

D² = 4² + 4² - 2(4)(4)cos(116)

D² = 46.0278767

D = 6.784384769

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