Explanation:
1)
Given data:
Moles of Al(OH)₃ = 0.52 mol
Moles of HCl consume = ?
Solution:
Chemical equation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
Now we will compare the moles of HCl and Al(OH)₃.
Al(OH)₃ : HCl
1 : 3
0.52 : 3×0.52 = 1.56 mol
1.56 moles of HCl are consumed with 0.52 moles of Al(OH)₃ .
2)
Given data:
Moles of water produced = ?
Moles of Al(OH)₃ react = 1.35 mol
Solution:
Chemical equation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
Now we will compare the moles of H₂O and Al(OH)₃.
Al(OH)₃ : H₂O
1 : 3
1.35 : 3×1.35 = 4.05 mol
4.05 moles of H₂O are produced from 1.35 moles of Al(OH)₃ .
3)
Given data:
Moles of water produced = ?
Moles of HCl react = 1.98 mol
Solution:
Chemical equation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
Now we will compare the moles of H₂O and HCl.
HCl : H₂O
3 : 3
1.98 : 1.98
1.98 moles of H₂O are produced from 1.98 moles of HCl.
4)
Given data:
Moles of Al(OH)₃ required = ?
Moles of HCl react = 65 mol
Solution:
Chemical equation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
Now we will compare the moles of HCl and Al(OH)₃.
HCl : Al(OH)₃
3 : 1
65 : 1/3×65 = 21.67 mol
65 moles of HCl react with 21.67 moles of Al(OH)₃.
5)
Given data:
Moles of iron produced = 5.61 mol
Moles of CO required = ?
Solution:
Chemical equation:
Fe₂O₃ + 3 CO → 2Fe + 3CO₂
Now we will compare the moles of iron and CO.
Fe : CO
2 : 3
5.61 : 3/2×5.61 = 8.4 mol
For the production of 5.61 moles of Fe 8.4 moles of Co are required.
6)
Given data:
Moles of CO react = 16.8 mol
Moles of Fe₂O₃ required = ?
Solution:
Chemical equation:
Fe₂O₃ + 3 CO → 2Fe + 3CO₂
Now we will compare the moles of Fe₂O₃ and CO.
CO : Fe₂O₃
3 : 1
16.8 : 1/3×16.8= 5.6 mol
5.6 moles of Fe₂O₃ required to react with 16.8 moles of CO.
