Question

Find the zeros of f(x) = 3x^2 + 3x - 18.

{3, -2}
{-3, 2}
{-3, -2}

Answer 1

Answer:

(-3, 2)

Step-by-step explanation:

The given function is:

$f(x) =3x^2 + 3x - 18.$

We equate the function to zero and solve for values for x.

This implies that:

$3x^2 + 3x - 18 = 0$

Dividing through by 3.

$\implies x^2 +x - 6=0$

$\implies x^2 +3x -2x- 6= 0$

$\implies x(x+3)-2(x + 3= 0$

$\implies (x-2)(x + 3)= 0$

This implies that;

x - 2 =0, or

x + 3 = 0

Therefore x = 2 or x = - 3 are the zeros of the function.