Answer:
[tex]\ln( \frac{8}{25} ) = 3v - 2u[/tex]
Step-by-step explanation:
We have that
[tex]u= \ln(5) [/tex]
and
[tex]v = \ln2[/tex]
This implies that;
[tex]5 = {e}^{u} [/tex]
and
[tex]2 = {e}^{v} [/tex]
Now find and expresion for
[tex] \ln( \frac{8}{25} ) [/tex]
Which is
[tex]\ln( \frac{8}{25} ) = ln(8) - ln(25) [/tex]
[tex]\ln( \frac{8}{25} ) = ln( {2}^{3} ) - ln( {5}^{2} ) [/tex]
[tex]\ln( \frac{8}{25} ) = 3 ln( {2} ) - 2ln(5) [/tex]
[tex]\ln( \frac{8}{25} ) = 3v - 2u[/tex]